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MC-281: actually 2 ∞ ∑ n = 1 2 n ∑ k = 1 ( − 1 ) n + 1 ( 2 π ) 2 n ( 2 n − k + 1 ) ! ( 1 2 π i ) k = 1

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MC-281: actually 2 ∞ ∑ n = 1 2 n ∑ k = 1 ( − 1 ) n + 1 ( 2 π ) 2 n ( 2 n − k + 1 ) ! ( 1 2 π i ) k = 1
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